Solve for x.2. y = −3x2 − 12x − 7 y = - 3 x 2 - 12 x - 7. To find the axis of symmetry, we do x = -b/ (2a). Step 1.1. f min f min x = ax2 + bx+c x = a x 2 + b x + c occurs at x = − b 2a x = - b 2 a.1. Substitute the known values of , , and into the formula 99. y = 3x2 − 12x + 11 y = 3 x 2 - 12 x + 11. Linear equation. The maximum of a quadratic function occurs at . Tap for more steps x = y2 12 x = y 2 12. Rewrite the equation in vertex form. In this case, there is no real number that makes the expression undefined.4. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. Find the Vertex Form y=-3x^2+12x-7. Use the form , to find the values of , , and . Set y y equal to the new right side. Find the properties of the given parabola.1. Find the y-value when x = - 2. Factor. y = −3(x+2)2 +10 y = - 3 ( x + 2) 2 + 10 Alan P. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C.Place those points on the graph, and reunite them with a line and you'll get your graphical representation of the Solve y=3x^2+12x-13 | Microsoft Math Solver.2. Rewrite in slope-intercept form. Identify the vertex for the graph of y = 3x 2 + 12x + 5.1. Step 12. Algebra. Directrix: y = −13 12 y = - 13 12. What are quadratic equations?. Tap for more steps Direction: Opens Down. The vertex is at (2, -14). Vertex: (2,2) Explanation: y = −3x2 +12x−10 Use completing of the squares to put the equation in standard form: y = a(x−h)2 +k What is the the vertex of y = 3x2 − 12x − 24 ? The vertex of the parabola is at (2,-36) Explanation: The equation of parabola is in the form of ax^2+bx+c; here a=3 , b=-12 and c=-24 We know the x-co Find the Vertex y=3x^2+12x+9. Directrix: y = −13 12 y = - 13 12.1.1. Tap for more steps Step 1. We know this even before plotting "y" because the coefficient of the first term, -3 , is negative (smaller than zero). Find the value of using the formula. Simplify . Tap for more steps Step 1.1 Use the form , to find the values of , , and . Complete the square for . Factor out of .1. Tap for more steps Step 1. Tap for more steps Step 1.2.1. Tap for more steps y = 24. Tap for more steps y = −3(x−2)2 +4 y = - 3 ( x - 2) 2 + 4. By the Sum Rule, the derivative of with respect to is . x = - 2 is a local maximum. which graph represents the function y=3x^2+12x-6? y intercept of -8, lowest point is -18, starts as negative then turns positive. Hence the x intercepts are x=1 and x =3. Step 1.1. This is a table of possible values to use when graphing the equation. y=3x2-12x No solutions found Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : y-(3*x^2-12*x)=0 Step Algebra. Substitute the known values of , , and into the formula and What is the maximum value of slope of the curve y = −x 3 + 3x 2 + 12x − 5 ? class-12; Share It On Facebook Twitter Email. Rewrite the equation in vertex form.2. Use the slope-intercept form to find the slope and y-intercept. Complete the square for −3x2 +12x−7 - 3 x 2 + 12 x - 7. Rewrite in slope-intercept form.1. Tap for more steps Step 1.3. Tap for more steps x = 1 2.1. which equation matches the graph shown below? y=2x^2+8x-5. Multiply by . The equation has a maximum value with a y-coordinate of -27. Find the Vertex y=-3x^2-12x-7.2. Graph y=-3x^2+12x-1. Raise to the power of . which equation matches the graph shown below? y=2x^2+8x-5.3. Tap for more steps Step 1.1. Now the clever bit: Take the coefficient of x , which is 4 , divide by two, giving 2 , and finally square it giving 4. Solve the equation for . Tap for more steps Slope: − 2 3 - 2 3. ( - 2, 24) is a local maxima.2. Step 1. h = −2 h = - 2. Complete the square for x2 −12x+40 x 2 - 12 x + 40.1. Tap for more steps Step 2. Math notebooks have been around for hundreds of years. Two numbers r and s sum up to 4 exactly when the average of the two numbers is \frac{1}{2}*4 = 2. Step 1. The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down. Rewrite the equation in vertex form. The minimum of a quadratic function occurs at x = − b 2a x = - b 2 a. x = -12/ (2 (3)) x = -12/6 x = -2 So the axis of symmetry is x Find the Local Maxima and Minima f(x)=2x^3+3x^2-12x-10. Use the form , to find the values of , , and . Multiply by .1. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a. y = 3(x − 2)2 − 11. So, we have 4. Directrix: y = 97 12.alumroF citardauQ eht gnisU spetS .1. 12x = y2 12 x = y 2. Tap for more steps x = y2 12 x = y 2 12. x2−x−2 x 2 - x - 2. a ≠ 1, and a = 2, so divide all terms y=3x2-12x No solutions found Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : y-(3*x^2-12*x)=0 Step Find the Axis of Symmetry y=3x^2-12x-13. We know that a = 3 and b = 12, so we plug them into the equation. y = 3x + 2 y = 3 x + 2. Step 1. answered Jun 10, 2021 by Eeshta01 (31. Find the Concavity f (x)=2x^3-3x^2-12x+18. Complete the square for . Find the Vertex y=3x^2-12x+6. Graph y=3x^2-12x+7. Subtract 5/3 from both side of the equation : x2+4x = -5/3. Complete the square for 3x2 −12x+4 3 x 2 - 12 x + 4. Factor. Step 2. A parabola has an axis of symmetry and a vertex. Tap for more steps 3(x−2)2 −11 3 ( x - 2) 2 - 11 Set y y equal to the new right side. y = x2 − 12x + 40 y = x 2 - 12 x + 40. James D. y = 3x2 y = 3 x 2. Step 1.1.5. Find the properties of the given parabola. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. Tap for more steps y = −3(x+2)2 +15 y = - 3 ( x + 2) 2 + 15. Algebra.2 + 12x - 33 O A.1. Find the Vertex y=-3x^2+12x-8.6. Free slope intercept form calculator - find the slope intercept form of a line given two points, a function or the intercept step-by-step. Step 1. The values of r and s are equidistant from the center by an unknown quantity u.2. Rewrite as . Rewrite the equation in vertex form. Tap for more steps Step 1.3. is a local maxima.1. Tap for more steps Direction: Opens Up. Step 1. The parent function is the simplest form of the type of function given. Select a few x x values, and plug them into the equation to find the corresponding y y To complete the square when a is greater than 1 or less than 1 but not equal to 0, divide both sides of the equation by a. y = 3(x2 + 4x) The coefficient 4 will be divided by 2 and the result will be squared giving 4. We transform the equation by Completing the square method.1. Tap for more steps y = 13 y = 13 Find the point at x = 0 x = 0. Rewrite the equation in vertex form. Tap for more steps Step 1. Consider the vertex form of a parabola. Rewrite the equationin vertexform. Complete the square to convert to vertex form. It is possible that the equation is already in that form. Where -. h = − Graph y=-3x^2+12x-5.1.1.2. Use the form , to find the values of , , and . y=3x^{2} en. View solution steps. . Use the quadratic formula to find the solutions. Use the slope-intercept form to find the slope and y-intercept.1 Pull out like factors : Solve Using the Quadratic Formula 3x^2=-12x-15. y = 2x3 + 3x2 - 12x + 7.1. Step 1. Since is constant with respect to , the derivative of with respect to is . Factor out of . Step 2.1. Tap for more steps Step 1. Rewrite the equation in vertex form. Complete the square for . Tap for more steps Step 1. 12x = y2 12 x = y 2. Use the vertex form, y = a(x−h)2 +k y = a ( x - h) 2 + k, to determine the values of a a, h h, and k k. These are all Called Systems of Equations in Mathematics: Q1.1 Free functions vertex calculator - find function's vertex step-by-step Steps Using the Quadratic Formula Steps for Completing the Square View solution steps Solve for y y = 11 − 12x − 3x2 Graph Quiz Quadratic Equation y = −3x2 −12x+11 Similar Problems from Web Search How do you find the zeros, real and imaginary, of y = −x2 − 12x + 11 using the quadratic formula? Precalculus Graph y=2x^3+3x^2-12x y = 2x3 + 3x2 − 12x y = 2 x 3 + 3 x 2 - 12 x Find the point at x = −2 x = - 2. Find the value of using the formula. Find the properties of the given parabola. Rewrite the equation in vertex form. Factor out of . Algebra. XXXXXXXX with a vertex at (a,b) Given y = −3x2 +12x − 9. Find the Vertex y=-3x^2-12x+3. Tap for more steps Free functions vertex calculator - find function's vertex step-by-step dxd (x − 5)(3x2 − 2) Integration. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. y = 3x2 + 12x − 10 y = 3 x 2 + 12 x - 10. Long addition.1. Complete the square for . Select a few x x values, and plug them into the equation to find the corresponding y y To complete the square when a is greater than 1 or less than 1 but not equal to 0, divide both sides of the equation by a. Solve by Factoring 3x^2-12x=0. Vertex: (2, 8) Focus: (2, 95 12) Axis of Symmetry: x = 2. Find the properties of the given parabola. Long substraction.2. The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down. Jul 22, 2015 Re-write the given equation in "vertex form" to get: XXXX vertex at (2,3) Explanation: The general "vertex form" for a parabola is XXXXy = m(x −a)2 + b XXXXXXXX with a vertex at (a,b) Given y = −3x2 +12x − 9 Extract m XXXXy = ( −3)(x2 − 4x) −9 Complete the square: XXXXy = ( −3)(x2 − 4x + 4) − 9 + 3(4) XXXXy = ( −3)(x − 2)2 + 3 Free Parabola Vertex calculator - Calculate parabola vertex given equation step-by-step Graph y=3x^2+12x-6. Tap for more steps 6x2 + 6x−12 6 x 2 + 6 x - 12.1 Pull out like factors : y = - 3x2 + 12x - 4.1. 2(y 2 + 3y) = 18 / (3x 2 - 12x + 16) - 9 (y 2 + 3y) = 9 / (3x 2 - 12x + 16) - 9/2 (divide by 2). Send us Feedback. Step 1. Solve.1. y = 2x3 + 3x2 − 12x + 5 y = 2 x 3 + 3 x 2 - 12 x + 5.1.6. a = −3 a = - 3. Factor out of . a = −3 a = - 3. Given - y=3x^2-12x+1 x= (-b)/ (2a)= (- (-12))/ (2xx3)=12/6=2 At (x=2) y=3 (2^2)-12 (2)+1=12-24+1=-11 Vertex (2,-11) The vertex form is - y=a Factor 3x^3-12x. Find the properties of the given parabola. Long multiplication. Tap for more steps Step 1. Step 1.2. There are no x-intercepts.3.2. y = 3x2 +12x. Factor 3 3 out of 3x2 +12x−36 3 x 2 + 12 x - 36. Use the form , to find the values of , , and . asked • 09/20/21 Find the points on the curve y = 2x3 + 3x2 − 12x + 3 where the tangent line is horizontal. y = −3(x−2)2 +5 y = - 3 ( x - 2) 2 + 5.3 + 2 )2 + x ( 3 - = y 3+ 2)2+x(3− = y . Rewrite the equation in vertex form. Rewrite the equation as 12x = y2 12 x = y 2.2. Find the properties of the given parabola. Use the form , to find the values of , , and . x of vertex: #x = (-b/2a) = 12/6 = 2# y of vertex: # f(2) = 3(4) - 12(2) + 17 = 5# Vertex form: # f(x) = 3(x - 2)^2 + 5# To find y-intercept, make x = 0 -> y = 17 To find x-intercept solve #f(x) = 3x^2 - 12x + 17 = 0# D = 144 - 204 = -60 < 0. Set the first derivative equal to 0 then solve the equation 6x2 + 6x - 12 = 0. Find the value of using the formula. f (x) = 2x3 +3x2 − 12x+5 f ( x) = 2 x 3 + 3 x 2 - 12 x + 5. My Notebook, the Symbolab way.1. Tap for more steps Step 1. x→−3lim x2 + 2x − 3x2 − 9. we get the below whose vertex is (-2, -18) Algebra. Instructions: Given the equation of the circle, find the center and radius. Step 7. Vertex: (2, 12) Focus: (2, 143 12) Axis of Symmetry: x = 2. Tap for more steps Direction: Opens Up Vertex: (2,−2) ( 2, - 2) … Solve y=3x^2-12x | Microsoft Math Solver. Tap for more steps Step 1. Get immediate feedback and guidance with step-by-step solutions and Wolfram Problem Generator Calculus. The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down.2 Solving 3x2+12x+5 = 0 by Completing The Square . Solve for x. Tap for more steps Step 1. y 2 + 3y + 9/4 = 9 / (3x 2 - 12x + 16) - 9/2 + 9/4 (complete the square) Which statement is true about the extreme value of the given quadratic equation? y = -3. f(x) = 2x3 - 3x2 - 12x + 18.1. Find the first derivative of the function. Directrix: y = 145 12. Try this example now! » Graph y=-3x^2-12x-9.6.1. 0 C.1. Step 1. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. The vertex of the function is (2, 28) and the y-intercept of the function is (0, 40). Tap for more steps 3(x−2)(x +6) 3 ( x - 2) ( x + 6) Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions Algebra. Divide each term in 12x = y2 12 x = y 2 by 12 12 and simplify. Evaluate. Tap for more steps Step 1. Given: y = 3x^2 + 12x + 5 a = 3, therefore, add 0 in the form 3h^2 - 3h^2 to the equation: y = 3x^2 + 12x + 3h^2 Graph y=3x^2-5. Step 1. Solve the equation for .2. These are the local extrema for f(x) = 2x3 + 3x2 - 12x + 4. a = −3 a = - 3. Step 1. Set y y equal to the new right side. Replace the variable with in the expression.1. Step 2. Given the function y = 3x^2 - 12x + 9. Select two x x values, and plug them into the equation to find the corresponding y Graph y=3x^2-12x+9. a = −3 a = - 3.1 Explore math with our beautiful, free online graphing calculator. Example: "y = 3x2 + 12x + 7" becomes "y = 3 (x + 2)2 - 5", with vertex (-2, -5). Step 3. y = −3x2 − 12x − 5 y = - 3 x 2 - 12 x - 5. Subtract from both sides of the equation.6. Tap for more steps Step 1. y2 = 12x y 2 = 12 x. Substitute the known values of , , and into the formula y=x^2+1 (Graph Example), 4x+2=2(x+6) (Solve Example) Algebra Calculator is a calculator that gives step-by-step help on algebra problems.1. Step 1. The domain of the expression is all real numbers except where the expression is undefined. Find the value of using the formula. How to determine the vertex? The equation of the function is given as. Multiply by .1. y = 3(x −2)2 −8 y = 3 ( x - 2) 2 - 8.6. Step 1. Divide both sides of the equation by 3 to have 1 as the coefficient of the first term : x2+4x+ (5/3) = 0. Raise to the power of . Step 4. Integration.1.1. Rewrite the equation in vertex form. Find the properties of the given parabola. (1, - 3) is a local minima. This is the number to be added and subtracted inside the grouping symbol. Step 1. Find the Vertex y=3x^2+12x-12. Step 1. Limits. Tap for more steps 3(x−2)(x +6) 3 ( x - 2) ( x + 6) Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions Find the Vertex y=-3x^2-12x-7.1.1. View solution steps. Graph f(x)=3x^2+12x+9.2 + x 3 2 - = y 2+x3 2 − = y spets erom rof paT . In the form y = a (x −p)2 + q, the vertex can be found at (p, q). If is negative, the maximum value of the function is . 22 2 2. Find the properties of the given parabola.3. Solution.1. Tap for more steps Answer link. Consider the vertex form of a … Algebra. 1- For x = 0, y = -3 (Since the y-intercept is b = -3).

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Tap for more steps Step 1. This is a table of possible values to use when graphing the equation.2. Previous. Step 1. Substitute the known values of , , and into the Algebra. Answer link. Step 1. Tap for more steps Slope: − 2 3 - 2 3.1. 3. Tap for more steps Step 1. Complete the square for . Slope: 4 y-intercept: −20 Explanation: Method 1 For a linear equation in standard form: Ax+By = C (XXX) How do you solve the system of equations 3x + 9y = 1 and −12x + 3y = 16 ? x= −3947 and y = 3920 Explanation: Lets call 3x+9y = 1 the first equation and −12x+3y = 16 Answer: The correct option is (C) x = 2. An example with three indeterminates is x³ + 2xyz² − yz + 1. y = −3x2 − 12x + 3 y = - 3 x 2 - 12 x + 3. Find the derivative. The equation is already simplified. a = 3 a = 3. Step 1. Algebra. y-intercept: (0,2) ( 0, 2) Any line can be graphed using two points.6. Tap for more steps Step 1. Tap for more steps Step 1. The final answer is . Tap for more steps Step 1. Tap for more steps y = 3(x +2)2 −22 y = 3 ( x + 2) 2 - 22. Tap for more steps Step 1. Tap for more steps Step 1. Tap for more steps x = 1, - 2. Rewrite the equation in vertex form.). 22 2 2. The vertex form of the equation of a parabola that opens upward (or downward) is: y = a(x - h)^2 + k where (h, k) is the vertex and "a" is the coefficient of the x^2 term. x = 0 x = 0. And 6x − 12 is negative up to x = 2, positive from there onwards. Tap for more steps y = 20 y = 20.3. Step 1. Add 5/3 to both side of the equation : x2+4x = 5/3. Step 2. Rewrite the equation in vertex form. which of the following functions has a rate of change that stays the same? y=19x-10.3. Vertex: (2,−1) ( 2, - 1) Focus: (2,−11 12) ( 2, - 11 12) Axis of Symmetry: x = 2 x = 2. XXXXy = m(x −a)2 + b.1. Tap for more steps y = −3(x+2)2 +5 y = - 3 ( x + 2) 2 + 5. Tap for more steps Step 1.1. Step 3. Rewrite the equation in vertex form. Factor 3x^2+12x-36.1. What is the vertex for this function? y = 3x^2 + 12x + 5 The answer can't be (-2, -7) it's not an option (2, 41) (2, 7) (-2, 41) (-2, 7) loading. Step 1. Find the Vertex y=3x^2-12x+6.3. 3x2 + 12x − 36 3 x 2 + 12 x - 36. … Graph y=-3x^2-12x-9. Solving word problems by rewriting information as equations. Tap for more steps Step 1.2. 3x2 + 12x − 36 3 x 2 + 12 x - 36. Evaluate. chevron left. Tap for more steps Step 1.1. Step 16. Tap for more steps Step 1. Step 1. factor out 3. Find the properties of the given parabola. x2−x−2 x 2 - x - 2. B. Tap for more steps Step 2. Tap for more steps −3(x− 2)2 +5 - 3 ( x - 2) 2 + 5.1.2. Step 1.3. Substitute for and find the result for .6. Factor. Tap for more steps Step 1. Add 40/3 to both side of the equation : x2+4x = 40/3.1. x^2-x-2.1.6.1. Tap for more steps Step 1.3.6.1. Find the properties of the given parabola. Use the vertex form, y = a(x−h)2 +k y = a ( x - h) 2 + k, to determine the values of a a, h h, and k k. Find the Vertex Form y=3x^2-12x+7. As an example let's complete the square for this quadratic equation: 2x2 − 12x + 7 = 0 2 x 2 − 12 x + 7 = 0. Factor 3x 3 x out of 3x2 −12x 3 x 2 - 12 x.1.2. Set y y equal to the new right side. Rewrite the equation in vertex form. Simplify . One way to determine this answer: (I'm going to put it into graphing form. Given that the coefficient (constant number in front) of x^2 is negative 3, for any NEGATIVE coefficient, the graph is a SAD smiley (has a maximum point). Algebra.1. Tap for more steps Step 1. Tap for more steps Step 1. Tap for more steps y = −3(x+2)2 +7 y = - 3 ( x + 2) 2 + 7. Step 12. y = −3x2 + 12x − 7 y = - 3 x 2 + 12 x - 7. Step 1.6. Find the properties of the given parabola. Solve y=3x^2+12x+5 | Microsoft Math Solver.3. Find the properties of the given parabola. Substitute the known values of , , and into the 3. Tap for more steps Step 1. Step 1. Rewrite the equation in vertex form. h = −2 h = - 2. Tap for more steps Step 1. Step 1. Select two x x values, and plug them into the equation to find the corresponding y y values. Use the vertex form, y = a(x−h)2 +k y = a ( x - h) 2 + k, to determine the values of a a, h h, and k k.2.4. Rewrite the equation in vertex form. Find the first derivative. Get help on the web or with our math app. Equation: (x−8)2+(y−7)2=25. Factor out of .1.2 Consider the vertexform of a parabola. Step 2. Matrix. Tap for more steps Step 1. The given equation is the equation of a parabola that opens upward (or downward). y = 3x2 + 12x − 12 y = 3 x 2 + 12 x - 12. Please see the explanation. This is the same as factoring out the value of a from all other terms. The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down. Rewrite the equation in vertex form. Step 1.1. Tap for more steps 3(x2 − 4x+4) 3 ( x 2 - 4 x + 4) Factor using the perfect square rule.5). Given a function and its curve , to find any stationary point (s) we follow three steps : Step 1: find. The final answer is .2.1. Complete the square for 3x2 −12x+7 3 x 2 - 12 x + 7. Step 2. Step 1. Step 1. Graph functions, plot points, visualize algebraic equations, add sliders, animate graphs, and more. Consider the vertex form of a parabola. Set the derivative equal to 0 0 then solve the equation 6x2 +6x−12 Solve Quadratic Equation by Completing The Square. Steps Using the Quadratic Formula. Step 1.1. So we now have the 2 points A (0, -3) and B (2, -2). Rewrite the equation in vertex form.1. View … Free math problem solver answers your algebra homework questions with step-by-step explanations. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics The unique answer is (2, -1.1. Rewrite the equation in vertex form. Tap for more steps Step 1. Factor 3 3 out of 3x2 −12x+12 3 x 2 - 12 x + 12. The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down. Substitute the known values of , , and into the The equation has 2 real roots How to determine the number of real roots? The equation is given as: [tex]y = 3x^2 + 12x - 12[/tex] Calculate the determinant usi… Square root of fraction or number by prime factorization. y-intercept: (0,2) ( 0, 2) Any line can be graphed using two points. The equation has a minimum value with a y-coordinate of -21. The equation in vertex form is given as: y = a (x - h) ² + k where a, h, and k are constant. y = −3x2 + 12x − 8 y = - 3 x 2 + 12 x - 8. x = -b/2a. Tap for more steps Step 1. y = 3x2 − 12x + 11 y = 3 x 2 - 12 x + 11. h = 2 is the x - co-ordinate of vertex. Long division. y = x3 + x2 − 12x y = x 3 + x 2 - 12 x. Algebra. g(x) = 3x2 g ( x) = 3 x 2.1. Substitute the known values of , , and into the formula and factor quadratic x^2-7x+12; expand polynomial (x-3)(x^3+5x-2) -16 with x^4-8x^3+25x^2-46x+16; quotient of x^3-8x^2+17x-6 with x-3; remainder of x^3-2x^2+5x-7 divided by x-3; roots of x^2-3x+2; View more examples; Access instant learning tools. Assume that y = x2 y = x 2 is f (x) = x2 f ( x) = x 2 and y = 3x2 y = 3 x 2 is g(x) = 3x2 g ( x) = 3 x 2. Tap for more steps Direction: Opens Down. Steps for Completing the Square. 100.1. Solve your math problems using our free math solver with step-by-step solutions. Find the Vertex Form y=-3x^2+12x-7. Given: y=3x²+12x-6. Tap for more steps y = 20 y = 20 Find the point at x = −1 x = - 1.3. Exact Form: 代数.2.0k points) selected Jun 11, 2021 by Daakshya01 . Use the form , to find the values of , , and . Solve by Completing the Square 3x^2-12x+1=0. See More Examples » For example, enter 3x+2=14 into the text box to get a step-by-step explanation of how to solve 3x+2=14. Tap for more steps Step 1. Use the form , to find the values of , , and . Consider the vertex form of a parabola. Tap for more steps Slope: 3 3. Consider the vertex form of a parabola. To find the vertex of a standard quadratic equation y = ax^2 + bx + c, we first use the formula -b/(2a) to find the x value of the vertex, or x_v. Step 1. Divide both sides of the equation by 3 to have 1 as the coefficient of the first term : x2-4x- (8/3) = 0. Factor out of . Tap for more steps Step 1.2. Step 1. Use the slope-intercept form to find the slope and y-intercept. Rewrite the equation in vertex form. Step 1. The derivative is: y' = 3x 2 − 12x + 12. Step 1. Step 3.1.1. y = −3x2 + 12x − 7 y = - 3 x 2 + 12 x - 7. Find the value of using the formula. h = −2 h = - 2. Now the clever bit: Take the coefficient of x , which is 4 , divide by two, giving 2 , and finally square it giving 4. The transformation being described Complete the square for each equation and enter the vertex " (h, k)". Tap for more steps Step 1. Add 8/3 to both side of the equation : x2-4x = 8/3. 2^2. Find the Maximum/Minimum Value y=3x^2-4x-2. Graph y^2=12x. Find the properties of the given parabola. Write f (x) = 3x2 − 12x+4 f ( x) = 3 x 2 - 12 x + 4 as an equation. Step 1. So, the vertex is (-2, -27). f (x) is concave upward from x = 2 on. y=3x2-12x No solutions found Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : y-(3*x^2-12*x)=0 Step Graph y=2x^3+3x^2-12x.1. Graph y=3x+2. Tap for more steps Step 1.2. Factor out of . Step 1. Precalculus Find the Vertex Form y=3x^2-12x+1 y = 3x2 − 12x + 1 y = 3 x 2 - 12 x + 1 Complete the square for 3x2 −12x+1 3 x 2 - 12 x + 1. Step 2. Step 1.1. Add and . Find the Vertex y=3x^2+12x-10. k = − 11 is the y - co-ordinate of vertex. Tap for more steps 3(x−2)2 3 ( x - 2) 2.1.3.2. Step 17. Simplify the result. Consider the vertex form of a parabola. The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down. 100.1. Tap for more steps Step 1. Step 1. As an example let's complete the square for this quadratic equation: 2x2 − 12x + 7 = 0 2 x 2 − 12 x + 7 = 0. Step 1. Tap for more steps 3(x−2)2 −11 3 … In mathematics, a polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and positive … Algebra. Since a is +ve the parabola represented by this equation is opening upwards and the x - coordinate of its vertex is given by the expression. ∫ 01 xe−x2dx. Remove parentheses. Step 1. Solve for x. Unit converter. erauqS ehT gnitelpmoC yb 0 = 8+x21-2x3 gnivloS 2. y = 3(x −2)2 −11 y = 3 ( x - 2) 2 - 11 In mathematics, a polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and positive-integer powers of variables. The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down.2. The axis of symmetry is a vertical line the divides the parabola into to equal halves. y = 12x - 3x2. Find the properties of the given parabola. Add and . a ≠ 1, and a = 2, so divide all terms Algebra. Substitute the known values of , , and into the formula Find the Vertex y=3x^2-12x+17.2.1. Tap for more steps Step 1. 3x² - 12x can be written as: Popular Problems Algebra Find the Vertex Form y=-3x^2-12x-2 y = −3x2 − 12x − 2 y = - 3 x 2 - 12 x - 2 Complete the square for −3x2 −12x−2 - 3 x 2 - 12 x - 2. place a point on the coordinate grid to show each x-intercept of the fu Get the answers you need, now! y = 3(2)² - 12(2) + 9 = -3. Step 1.1. 頂点形、 y = a(x− h)2 +k y = a ( x - h) 2 + k 、を利用して a a 、 h h 、 k k の値を求めます。. Substitute the values a = 3 a = 3, b Two numbers r and s sum up to 4 exactly when the average of the two numbers is \frac{1}{2}*4 = 2. Complete the square for .1. Step 1.2. Graph y=x^3+x^2-12x. Substitute the known values of , , and into the Free graphing calculator instantly graphs your math problems. y = −3x2 − 12x + 3 y = - 3 x 2 - 12 x + 3. Since both terms are perfect squares, factor using the difference of squares formula, where and . Free math problem solver answers your algebra, geometry 3x2-12x Final result : 3x • (x - 4) Step by step solution : Step 1 :Equation at the end of step 1 : 3x2 - 12x Step 2 : Step 3 :Pulling out like terms : 3. Remove unnecessary parentheses. In vertex form, y = a (x - p)^2 + q, the vertex is located at the point (p, q) Therefore, there is no x intercept. Tap for more steps 3x(x−4) = 0 3 x ( x - 4) = 0.

 Step 1

. Differentiation. Step 1. Step 1. Find the value of using the formula. Step 2.1. Find the properties of the given parabola. The graphical representation of this function proves that there is no x intercept.2.1.2. The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down. The equation has a maximum value with a y-coordinate of -21. Step 1.1. a = −3 a = - 3. In y = a (x - h) 2 + k form here, h = 0 so (x - h) is just x, and k = 19. Tap for more steps Step 1.2. Tap for more steps −3(x+ 2)2 +10 - 3 ( x + 2) 2 + 10 Set y y equal to the new right side.2. Tap for more steps Step 1. Step 1. Step 1. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. h = −2 h = - 2.6.1.1. Differentiate using the Power Rule which states that is where . Now the clever bit: Take the coefficient of x , which is 4 , divide by two, giving 2 , and finally square it giving 4. Tap for more steps Step 1. Method: finding stationary points. Step 1. Rewrite the equation in vertex form. Free math problem solver answers your algebra, geometry, trigonometry, calculus 3. y = 3x^2 - 12x + 40. Step 1. Rewrite the equation in vertex form. y = 3x^2 + 12x - 15 y = 3 (x^2 + 4x + n - n) - 15 n = (b/2)^2 n = 4 y = 3 (x^2 + 4x + 4 - 4) - 15 y = 3 (x^2 + 4x + 4) - 12 - 15 y = 3 (x^2 + 4x + 4) - 27 y The numerical information gathered through observation is referred to as data.

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Subtract 8/3 from both side of the equation : x2-4x = -8/3.2.2. occurs at . #a=-3# #b=3# The graph of a quadratic equation is a parabola.2 Solving 3x2+12x-40 = 0 by Completing The Square . Tap for more steps Direction: Opens Up Vertex: (2,−2) ( 2, - 2) Focus: (2,−23 12) ( 2, - 23 12) Axis of Symmetry: x = 2 x = 2 Directrix: y = −25 12 y = - 25 12 Steps Using the Quadratic Formula Steps for Completing the Square View solution steps Solve for y Graph Quiz Quadratic Equation 5 problems similar to: Similar Problems from Web Search Free math problem solver answers your algebra homework questions with step-by-step explanations.. Tap for more steps Step 2. Tap for more steps Step 1. Now, plotting the graph which is attached below. Step 1. Evaluate.1. y = a(x − h)2 + k.1.1. Rewrite the equation in vertex form. Step 5.1.1. Step 2. Tap for more steps 6x2 + 6x - 12. Step 15. The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down. Complete the square for .1. Graph y=-3x^2+12x-1. Step 11. 3.1. Each parabola has a vertical line of Find the Horizontal Tangent Line y=2x^3+3x^2-12x+5.2 Solving 3x2+12x-5 = 0 by Completing The Square . Find the properties of the given parabola. Our math solver … Precalculus Graph y=2x^3+3x^2-12x y = 2x3 + 3x2 − 12x y = 2 x 3 + 3 x 2 - 12 x Find the point at x = −2 x = - 2. Find the value of using the formula. Factor out of . Remove parentheses. Find the point at x = −1 x = - 1. y-intercept: (0,2) ( 0, 2) Any line can be graphed using two points. Solve. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and 3x2-12x Final result : 3x • (x - 4) Step by step solution : Step 1 :Equation at the end of step 1 : 3x2 - 12x Step 2 : Step 3 :Pulling out like terms : 3.1. It can factor expressions with polynomials involving any number of vaiables as well as more complex functions. y = 3x2 − 12x + 7 y = 3 x 2 - 12 x + 7.3 Find the value of using the formula. Related Symbolab blog posts.1. Divide each term in by and simplify. Tap for more steps (x−6)2 +4 ( x - 6) 2 + 4. Step 1. Consider the vertex form of a parabola.2.6. Step 7. Divide both sides of the equation by 3 to have 1 as the coefficient of the first term : x2-4x+ (8/3) = 0. #f(x)=-3x^2+3x-2# The general formula for a quadratic equation is #ax^2+bx+c#. Select two x x values, and plug them into the equation to find the corresponding y Graph y=3x^2-12x+9.2. The parabola graph doesn't intersect the x-axis. Use the vertex form, y = a(x−h)2 +k y = a ( x - h) 2 + k, to determine the values of a a, h h, and k k.6. Complete the square for −3x2 +12x−7 - 3 x 2 + 12 x - 7. has as its line of symmetry given by: From equation (i), we have Find the Maximum/Minimum Value f(x)=-3x^2-12x-10.2. Select a few x values, and plug them into the equation to find the corresponding y values. Arithmetic. f (x) = x2 f ( x) = x 2. Find the Vertex y=3x^2+12x-10. Substitute the known values of , , and into the formula Find the Vertex y=3x^2-12x+17. Substitute the known values of , , and into the Algebra. Use the form , to find the values of , , and . Algebra.1. Tap for more steps −3(x− 2)2 +5 - 3 ( x - 2) 2 + 5. Tap for more steps 3(x−2)2 −8 3 ( x - 2) 2 - 8. 0 D.1. The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down. which graph represents the function y=3x^2+12x-6? y intercept of -8, lowest point is -18, starts as negative then turns positive. Add to both sides of the equation. Tap for more steps 3(x−2)2 −5 3 ( x - 2) 2 - 5. x^2-x-2. Step 1. Those are your turning points. If a a is positive, the minimum value of the function is f (− b 2a) f ( - b 2 a). Factor out of . The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down. Find the values where the derivative is undefined. You write down problems, solutions and notes to go Find the Vertex y=3x^2-12x+16. Find the properties of the given parabola. Factor 3 3 out of 3x2 +12x−36 3 x 2 + 12 x - 36. Rewrite the equation in vertex form. Tap for more steps y = − 2 3x+2 y = - 2 3 x + 2. Now the clever bit: Take the coefficient of x , which is 4 , divide by two, giving 2 , and finally square it giving 4.2. Solve your math problems using our free math solver with step-by-step solutions. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.1. Rewrite the equation in vertex form. Step 1. Find the Axis of Symmetry y=3x^2-12x-13. We know that a = 3 and b = -12: x = -b/(2a) = (-(-12))/(2(3)) = 12/6 = 2 To find the y value of the vertex we simply plug in the x value back into the equation and solve for y: y = 3x^2 - ….1. Find the x values where the second derivative is equal to 0. $y = 3 \exponential {x} {2} - 12 x $. vertices\:x=y^2; axis\:(y-3)^2=8(x-5) directrix\:(x+3)^2=-20(y-1) Calculate parabola foci, vertices, axis and directrix step-by-step. Axis of Symmetry is the line x = − 2. Consider the vertex form of a parabola. Find the point at . Simultaneous equation. Answer link. Steps for Completing the Square. Tap for more steps Step 2.1. Divide each term in by . Graph y=3x^2-12x+7.2. asked • 09/20/21 Find the points on the curve y = 2x3 + 3x2 − 12x + 3 where the tangent line is horizontal.) 2y 2 + 6y + 9 = 18 / (3x 2 - 12x + 16). Find the value of using the formula. Factor out of . An example of a polynomial of a single indeterminate x is x² − 4x + 7. Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k. Limits. Differentiate the function. And we'll find their coordinates using the equation. We could have also found, by intuition, that there are no x intercepts: In a quadratic x2+3y2-2x+12y+13=0 No solutions found Step by step solution : Step 1 :Equation at the end of step 1 : ( ( ( (x2) + 3y2) - 2x) + 12y) + 13 = 0 Step 2 :Equation at the end of step 2 : x2 - 2x + How many common tangents are possible between the two circles x2 + y2 − 2x − 4y + 1 = 0 and x2 + y2 − 12x − 16y + 91 = 0 ? The equation y = 3x² - 12x + 11 in vertex form is y = 3(x - 2)² + 7. Find the Vertex y=3x^2+12x-12. The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down. y = 3x2 −12x+4 y = 3 x 2 - 12 x + 4. Online math solver with free step by step solutions to algebra, calculus, and other math problems. Free math problem solver answers your algebra Graph Using a Table of Values y=-3x+2. Explanation: From the given equation. Find the Vertex Form y=x^2-12x+40. Describe the Transformation y=3x^2. Step-by-step explanation: We are given to select the correct option that gives the line of symmetry for the graph of the following equation: We know that the graph of a quadratic equation in the form . Use the and values to find where the maximum occurs. Use the form , to find the values of , , and .2. Tap for more steps Step 1.1. −3 2 − 12x − 9 y = - 3 x 2 - 12 x - 9. chevron Factor 3x^2-12x+12. Free math problem solver answers your algebra Graph Using a Table of Values y=-3x+2. Complete the squarefor .Algebra Graph y=3x^2-12x+10 y = 3x2 − 12x + 10 y = 3 x 2 - 12 x + 10 Find the properties of the given parabola. Makes sense given the shape of a This is referred to as the second derivative test. In a line graph, the information or data is represented as a series of markers, or dots, and is then connected to one another by a straight line. Use the form , to find the values of , , and . The vertex form is -. a = 3 a = 3. Step 8. Best answer. It is completely above the #(dy)/(dx) = d/(dx)[2x^3 + 3x^2 - 12x + 9]# #= 6x^2 + 6x - 12 = 0# There should then be two solutions.1. Precalculus. Tap for more steps Step 1. Rewrite the equation in vertex form. Subtract from . Tap for more steps Step 3. Divide both sides of the equation by 3 to have 1 as the coefficient of the first term : x2+4x- (40/3) = 0. Use the vertex form, y = a(x−h)2 +k y = a ( x - h) 2 + k, to determine the values of a a, h h, and k k. So the minimum value is y = -3. y = 3x2 +12x. Step 1. vertex: maximum point (2,3) Y-intercept = -9 X-intercept = 1 and 3 The given equation is -3x^2 +12x - 9 = y. Step 2. Rewrite the equation as 12x = y2 12 x = y 2.1. Step 1. Tap for more steps Step 1.2. Find the Axis of Symmetry y=-3x^2-12x-5. Divide both sides of the equation by 3 to have 1 as the coefficient of the first term : x2+4x- (5/3) = 0.7+x21-2^x3+3^x2=y stnioP lacitirC eht dniF arbegla ruoy srewsna revlos melborp htam eerF . Tap for more steps 3(x2 + 4x−12) 3 ( x 2 + 4 x - 12) Factor. And the inflection point is at x = 2: Calculus Index.1. is a local minima.2.3. To graph that function, we need at least 2 points from that line. The result can be shown in multiple forms. Step 1.1.2 Solving 3x2-12x-8 = 0 by Completing The Square . Step 3. Write the factored form using these integers. 3x2 − 12x = 0 3 x 2 - 12 x = 0. y2 = 12x y 2 = 12 x. y = 3 (x-2)^2-5 When given the form: y = ax^2+bx+c The vertex form is: y = a (x-h)^2+k where h = -b/ (2a) and k = a (h)^2+b (h)+c Given: y=3x^2-12x+7 We observe that a = 3 and substitute that value into the vertex form: y = 3 (x-h)^2+k" [1]" Compute h: h = 12/ (2 (3)) h = 2 Substitute into equation [1]: y = 3 (x-2)^2+k" [1. Tap for more steps y = 3(x +2)2 −24 y = 3 ( x + 2) 2 - 24. Step 1. Step 11. Step 1. y = −3(x−2)2 +5 y = - 3 ( x - 2) 2 + 5. Substitute the known values of , , and into the Free graphing calculator instantly graphs your math problems. Rewrite the equation in vertex form. Here is a graph showing the x-intercepts and the minimum value.2. Tap for more steps y = −3(x+2)2 +15 y = - 3 ( x + 2) 2 + 15. These are the local extrema for . Tap for more steps y = 0 y = 0 Find the point at x = 1 x = 1. Answer link. Complete the square: XXXXy = ( −3)(x2 − 4x + 4) − 9 + 3(4) XXXXy = ( … Factor 3x^2+12x-36. Tap for more steps Step 1. Select a few x values, and plug them into the equation to find the corresponding y values. 方程式を頂点形で書き換えます。. Tap for more steps Step 1. Given curve is Factor 3x^2-12x+9.3. 2y 2 + 6y = 18 / (3x 2 - 12x + 16) - 9. Step 1. The given equation is a quadratic equation of the form ax 2 + bx + c. round 2,746 to the nearest one hundred.1. 3x2 − 12x + 12 3 x 2 - 12 x + 12.1. See answer. Complete the square for . Now the clever bit: Take the coefficient of x , which is 4 , divide by two, giving 2 Pre-Algebra. Step 10. x = -12/2(3) = -2 Graph y=3x^2. y = (x− 6)2 +4 y = ( x - 6) 2 + 4. which of the following functions has a rate of … The general "vertex form" for a parabola is. Step 1.1. Consider the vertex form of a parabola. Move all the expressions to the left side of the equation. The Factoring Calculator transforms complex expressions into a product of simpler factors.1. a = −3 a = - 3. So: f (x) is concave downward up to x = 2. Tap for more steps Step 1. 3x2 = −12x − 15 3 x 2 = - 12 x - 15. Step 10. Solve: x - y = 1, -3x + 3y = 3 ===> There is No Solutions I will try to solve your equations… Algebra Graph y=3x^2-12x+10 y = 3x2 − 12x + 10 y = 3 x 2 - 12 x + 10 Find the properties of the given parabola. Find the point at x = −2 x = - 2. The values of r and s are equidistant from the center by an unknown quantity u. Algebra Factoring Calculator Step 1: Enter the expression you want to factor in the editor. Step 3 (if needed/asked): calculate the -coordinate (s) of the stationary point (s) by plugging the values 3.1.1.erauqS eht gnitelpmoC rof spetS . Step 1.2. Step 1. Find the Axis of Symmetry y=3x^2-12x-13 Step 1 Rewrite the equationin vertexform. Complete the square for .1 Find the Vertex of y = -3x 2-12x-2 Parabolas have a highest or a lowest point called the Vertex .2.1. The focus of a parabola can be found by adding to the y-coordinate if the parabola opens up or down.2. Step 2: solve the equation , this will give us the -coordinate (s) of any stationary point (s) . Steps Using the Quadratic Formula. Step 1. Divide by #6# to get: #0 = x^2 + x - 2# This factors as: #color(blue)((x-1)(x+2) = 0)# Therefore, two horizontal tangent lines can be found, one at #x = -2# and one at #x = 1#. Step 1. Find the value of using the formula. Step 1. Rewrite the equation in vertex form. Consider the vertex form of a parabola.1.1. This is the same as factoring out the value of a from all other terms. Substitute for and find the result for . Step 1. Find the Derivative - d/dx y=2x^3+3x^2-12x+8. 2^2. a = 3 is the coefficient of x2. Step 1.1. Find the properties of the given parabola. Step 2. Tap for more steps Step 1.2. Graph y^2=12x. Find the value of . Set y y equal to the new right side. Rewrite the equation in vertex form.1. Hopefully my explanation helps! Answer link. Rewrite the equation in vertex form. Rewrite the equation in vertex form. The vertex form of y=-3x^2+12x-8 is y=-3(x-2)^2+4 To derive vertex form y=a(x-h)^2+k from general quadratic form y=ax^2+bx+c, you can use completing the square y=-3x^2+12x-8 = -3 (x^2-4x+8/3) = -3 (x^2-4x +(-2)^2-(-2)^2 +8/3) = -3 ((x-2)^2 -4+8/3) = -3 ((x-2)^2 -4/3) = -3 (x-2)^2 -4 The vertex is easily determined by completing the square. y = x2 y = x 2. Complete the square for . Step 1.3. Tap for more steps Step 1. Tap for more steps y = 20 y = 20 Find the point at x = −1 x = - 1.2. Step 1. y = 3(x −2)2 −5 y = 3 ( x - 2) 2 - 5.2. Tap for more steps y = 12 y = 12.2.3. parabola-equation-calculator.1. Extract m. y = 3x2 − 4x − 2 y = 3 x 2 - 4 x - 2. If any individual factor on the left side of the equation is equal to 0 0, the entire expression will be equal to 0 0. Tap for more steps 3x2 + 12x+15 = 0 3 x 2 + 12 x + 15 = 0. k = −22 k = - 22. Set y y as a function of x x. Use the vertex form, y = a(x−h)2 +k y = a ( x - h) 2 + k, to determine the values of a a, h h, and k k. Tap for more steps Step 1. Step 2.2. James D. XXXXy = ( −3)(x2 − 4x) −9. Therefore a = 3; b = 12 and c = 5. Use the vertex form, y = a(x−h)2 +k y = a ( x - h) 2 + k, to determine the values of a a, h h, and k k. タップして手順をさらに表示してください…. Divide each term in 12x = y2 12 x = y 2 by 12 12 and simplify. Axis of symmetry: x = -2 Vertex: (-2, -14) This equation y = 3x^2 + 12x - 2 is in standard form, or ax^2 + bx + c. Find the properties of the given parabola. What is an equation? An equation is a mathematical statement that is made up of two expressions connected by an equal sign.1. Step 1.1. Tap for more steps 3(x2 + 4x−12) 3 ( x 2 + 4 x - 12) Factor. The line of symmetry is determined by the equation #x=(-b)/(2a)#. Substitute the known values of , , and into the formula 99. Solve.1 Complete the squarefor . Step 1. 1 Answer +1 vote . Vertex: (2,−1) ( 2, - 1) Focus: (2,−11 12) ( 2, - 11 12) Axis of Symmetry: x = 2 x = 2. Set y y equal to the new right side. si ot tcepser htiw fo evitavired eht ,eluR muS eht yB . Step 1. Step 2. Our parabola opens down and accordingly has a highest point (AKA absolute maximum) . Tap for more steps Step 1. Step 1. The second derivative is: y'' = 6x − 12.1. Simplify each term. Step 1. Graphing an ordered pair on a coordinate plane. Tap for more steps Direction: Opens Up. We have, y = 3x² - 12x + 11. Online math solver with free step by step solutions to algebra, calculus, and other … Precalculus Find the Vertex Form y=3x^2-12x+1 y = 3x2 − 12x + 1 y = 3 x 2 - 12 x + 1 Complete the square for 3x2 −12x+1 3 x 2 - 12 x + 1. Find the Vertex y=-3x^2-12x+3.1.